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(Solved): could someone help me with this inferential statistics question please. Thank you! A simple rando ...



A simple random sample is drawn from a population that is normally distributed. The sample mean is found to be 109 and the saMargin of error \( =\quad \) Round to 2 decimal places
\( 93 \% \) confidence interval: ( \( \quad \) ) Round to 2 decimal pl

could someone help me with this inferential statistics question please. Thank you!

A simple random sample is drawn from a population that is normally distributed. The sample mean is found to be 109 and the sample standard deviation is 10 . A. Compute the \( 93 \% \) confidence interval for the population mean \( \mu \) if the sample size is 18 . \( t \)-critical value \( =\quad \) Round to 4 decimal places Standard error of the mean \( =\quad \) Round to 4 decimal places Margin of error \( =\quad \) Round to 2 decimal places \( 93 \% \) confidence interval: ( Round to 2 decimal places B. Compute the \( 93 \% \) confidence interval for the population mean \( \mu \) if the sample size is 7 . \( t \)-critical value \( =\quad \) Round to 4 decimal places Standard error of the mean \( =\quad \) Round to 4 decimal places Margin of error \( =\quad \) Round to 2 decimal places \( 93 \% \) confidence interval: ( \( \quad \) ) Round to 2 decimal places C. Compare your answers to part A and part B. What can you conclude? We can conclude that if we decrease the sample size, the margin of error D. Compute the \( 92 \% \) confidence interval for the population mean \( \mu \) if the sample size is 18 . \( t \)-critical value \( =\quad \) Round to 4 decimal places Standard error of the mean \( =\quad \) Round to 4 decimal places Margin of error \( =\quad \) Round to 2 decimal places \( 92 \% \) confidence interval: ( \( \quad \), \( \quad \) Round to 2 decimal places E. Compare your answers to part \( \mathrm{A} \) and part C. What can you conclude? We can conclude that if we decrease the level of confidence, the margin of error Instructions \( \boldsymbol{\wedge} \)


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A) We are given, Sample mean, x?=109 Sample standard deviation, s=10 Sample size, n=18 We need to compute 93% confidence interval. So, At ?=0.07, the
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