(Solved): Cough and HeadacheCough and headaches are symptoms of many diseases, including respiratory infection ...

Cough and Headache At the $98\%$ confidence level, should be nurse inform the managers that their estimate of the proportion of common cold patients is incorrect? Yes. The observed sample proportion of patients with a common cold is higher than $15\%$. Yes, $15\%$ is not a plausible proportion because it is not within the $98\%$ confidence interval. No, $15\%$ is within the $98\%$ confidence interval, and it could be correct. No. The sample is random, and the observed proportion can be this high even when the actual proportion of common cold among patients is $15\%$. Question 6 1 pts Cough and Headache Type I Error occurs when a correct claim is rejected. Type II Error occurs when an incorrect claim is rejected. Based on the nurse's decision, what kind of error will she commit if she is wrong? Type II Error. None; she correctly rejected the managers claim. Both Type I and Type II Errors. Type I Error. Cough and Headache What is the observed proportion of patients that only had a common cold? Round your answer to 3 decimal places. Question 2 Cough and Headache Which of the following assumptions or rules are applicable in this scenario? Each outcome is independent of the others. Each trial has two outcomes. $\begin{array}{l}N?20n\\ np?10\text{ and }n(1?p)?10\end{array}$ Cough and Headache The count of common cold patients $(X)$ or their proportions $(\hat{p})$ are sample statistics. Which two of the following statements are correct about the distribution of these sample statistics. In the following statements, $p$ is the actual proportion of patients with a common cold, SD is the standard deviation of $X$, and $SE$ is the standard error of $\hat{p}$. $\hat{p}$ distribution is approximately Binomial(p, SE) X distribution is approximately Binomial $(n,p)$ $X$ distribution is exactly Binomial(n, p) $\hat{p}$ distribution is approximately $N(p,SE)$ Question 4 1 pts Cough and Headache Find the $98\%$ confidence interval for the actual proportion of patients with a common cold. $(0.173,0.287)$ $(0.166,0.295)$ $(0.176,0.285)$ $(0.150,0.230)$