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(Solved): Consider the instruction ADD DOG,AX in which the contents of the AX register and memory cell DOG ar ...
Consider the instruction ADD DOG,AX in which the contents of the AX register and memory cell DOG are added together and the results are stored in DOG. Choose the correct sequence of circuits which will correctly implement this instruction. TMP below is a temporary register. \[ \begin{array}{l} \text { IP->MAR } \\ \text { MEM(MAR) }>\text { MDR } \\ \text { MDR->IR } \\ \text { ADDR(IR) }>\text { MAR } \\ \text { MEM(MAR) }>\text { MDR } \\ \text { MDR+AX }>\text { MDR } \\ \text { MDR->MEM(MAR) } \\ \text { IP }+2 \rightarrow \text { IP } \\ \text { IP }>\text { MAR } \\ \text { MEM(MAR) }>\text { MDR } \\ \text { MDR->IR } \\ \text { ADDR(IR) }>\text { MAR } \\ \text { MEM(MAR) }>\text { MDR } \\ \text { MDR+AX->MDR } \\ \text { IP }+2 \rightarrow \text { IP } \\ \text { IP->MAR } \\ \text { MEM(MAR) }>\text { MDR } \\ \text { MDR-IR } \\ \text { AX }>\text { TMP } \\ \text { TMP+BX }>\text { TMP } \\ \text { TMP }>\text { AX } \\ \text { IP }+2>\text { IP } \\ \text { IP-PMAR } \\ \text { MEM(MAR) }>\text { MDR } \end{array} \] IP->MAR MEM(MAR) \( > \) MDR MDR->IR ADDR(IR) \( > \) MAR MEM(MAR) \( \rightarrow \) MDR MDR+AX->MDR MDR->MEM(MAR) IP \( +2 \rightarrow \) IP IP \( \rightarrow \) MAR MEM(MAR) \( \rightarrow \) MDR MDR \( \rightarrow \) IR ADDR(IR) \( > \) MAR MEM(MAR) \( > \) MDR \( \mathrm{MDR}+\mathrm{AX} \rightarrow \mathrm{MDR} \) IP \( +2 \rightarrow \) IP IP \( \rightarrow \) MAR MEM(MAR) \( \rightarrow \) MDR MDR \( > \) IR \( \mathrm{AX} \rightarrow \mathrm{TMP} \) \( \mathrm{TMP}+\mathrm{BX} \rightarrow \) TMP \( \mathrm{TMP} \rightarrow \mathrm{AX} \) IP \( +2 \rightarrow \) IP IP \( > \) MAR MEM(MAR) \( \rightarrow \) MDR MDR \( > \) IR ADDR(IR)->MAR MEM(MAR) \( > \) MDR \( \mathrm{MDR}+\mathrm{AX} \rightarrow \mathrm{AX} \) IP \( +2-> \) IP
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Option d is correct IP->MAR MEM(MAR)-> MDR MDR->IR ADDR(IR)->MAR MEM(MAR)->MDR
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