(Solved): Consider the following linear system written in augmented form: \[ \left[\begin{array}{rrrr|r} 3 & ...

Consider the following linear system written in augmented form: \[ \left[\begin{array}{rrrr|r} 3 & -3 & 6 & -1 & 8 \\ 0 & 4 & 5 & -9 & 3 \\ 0 & -7 & -5 & -3 & 1 \\ 0 & 2 & 9 & -6 & 1 \end{array}\right] \] If we use Gaussian elimination (with partial pivoting) to solve the linear system then the next stage in the elimination process would be: A \( E_{3} \rightarrow E_{3}-(7 / 4) E_{2}, E_{4} \rightarrow E_{4}+(1 / 2) E_{2} \) B Interchange equations 2 and 3 C Back substitution D Interchange equations 3 and 4 E \( \quad E_{3} \rightarrow E_{3}+(7 / 4) E_{2}, E_{4} \rightarrow E_{4}-(1 / 2) E_{2} \) F Interchange equations 1 and 3 G \( \mathrm{E}_{4} \rightarrow \mathrm{E}_{4}-(9 / 5) \mathrm{E}_{3} \) H Interchange equations 1 and 2 I \( \quad \mathrm{E}_{4} \rightarrow \mathrm{E}_{4}+(9 / 5) \mathrm{E}_{3} \) J Interchange equations 1 and 4 K Interchange equations 2 and 4