(Solved): Consider the flow on the driven side of a shock tube after the bursting of the diaphragm, as shown ...

Consider the flow on the driven side of a shock tube after the bursting of the diaphragm, as shown in Figure 2. The air in the driven side is initially $65\mathrm{kPa}$ and the temperature $440\mathrm{K}$. The probe is $3\mathrm{m}$ away from the diaphragm. The diaphragm breaks, releasing a shock that travels toward the probe, with a temperature ratio $\mathrm{T}2/\mathrm{T}1=1.813$ across it. After the shock passes, calculate the Mach number at location 2 (M2) and the Pitot pressure (P02 in $\mathrm{kPa})$ recorded by the probe. ütfen birini seçin: $\begin{array}{l}\text{ a.M2 }=2.150;P02=674\\ \text{ b.M2 }=0.554;P02=674\\ \text{ c.M2 }=1.043;P02=674\\ \text{ d.M2 }=1.043;P02=340\\ \text{ e.M2 }=2.150;P02=340\\ \text{ f.M2 }=0.554;P02=340\end{array}$ ORIGINALLLCATION OF DIAPHRAGM Figure 2