(Solved): Calculate the equilibrium points for the following autonomous ordinary differential equation dtdx ...

Calculate the equilibrium points for the following autonomous ordinary differential equation $$\frac{\mathrm{d}x}{\mathrm{d}t}=2x?12x^3$$ (to two decimal places if appropriate). $$\begin{array}{l}x=0.50,x=0.08,x=?0.08\\ x=0\text{ only }\\ x=0,x=0.41,x=?0.41\\ x=0,x=2.45,x=?2.45\\ x=0.50,x=0.29,x=?0.29\end{array}$$ Select the correct list of all orbit(s) for the following autonomous ordinary differential equation from the choices below: $$\frac{\mathrm{d}x}{\mathrm{d}t}=x^3+1$$ Select one: $$\begin{array}{l}\{?1\},(?1,0),(0,?)\\ (??,?)\\ (??,?1),(?1,1),(1,?)\\ \{?1\},(??,?1),(?1,?)\end{array}$$ there are no orbits for this differential equation