Calculate:
a. Add 40+j72 and (60)/(_(100))\deg
b. Subtract 25-j17 from 35+j50 and express the result in polar form.
c. ((4.1)/(_(-))64\deg )\times (13)/(_(13))\deg
d. ((4.1)/(_(-))64\deg )-:((13)/(_(13))\deg )
e. (3+j4)\times (5-j6)
f. (3+j4)-:(5-j6)
For the system shown in the figure below, find the sinusoidal expression for the current i_(1), if
i_(s)=20\times 10^(-6)sin(\omega t+90\deg )
i_(2)=6\times 10^(-6)sin(\omega t-60\deg )i_(s),i_(2), then calculate i_(1) in phasor. Finally, convert the result to a sinusoidal
expression. Pay attention to the quadrant and phase angle of i_(1).