(Solved): Boric acid, B(OH)3, undergoes an unusual equilibrium in water. The equilibrium and reaction diagram ...

Boric acid, B(OH)3, undergoes an unusual equilibrium in water. The equilibrium and reaction diagram are shown. B(OH), (aq) + H?O(1) B(OH)2 (aq) + H+ (aq) Potential energy B(OH)3 + H?O equal amounts of both At equilibrium will there be a higher concentration of starting materials (left) or products (right) in solution? O products Reaction progress starting materials B(OH)4 + H+