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(Solved): BIO 340 ACTIVITY \#5: HARDY-WEINBERG \& CHI-SQUARE ANALYSIS Name (Last, First) The following data w ...




BIO 340 ACTIVITY \#5: HARDY-WEINBERG \& CHI-SQUARE ANALYSIS
Name (Last, First)
The following data was obtained from a previou
III. Test U = Thiourea
Use the Chi-square stable, which can be found in the Chi-Square Analysis of Mendels Data page of your
BIO 340 ACTIVITY \#5: HARDY-WEINBERG \& CHI-SQUARE ANALYSIS Name (Last, First) The following data was obtained from a previous Bio 340 class. Date o. in reference papers regarding the USA population are also provided and will be used to dete. - the "Expected" frequency and counts. You will have to analyze the data and provide phenotype, genotype and allele frequencies as well as perform chi-square analyses. Complete every single empty square. For frequeticies, \( (0-E)^{2} / \mathrm{E} \) and \( \chi^{2} \) round to two decimal places. Use whole numbers for counts. people are counted in whole numbersi 1. Test 5 s Sodium benzoate: II. Test \( \mathrm{T} \) = Phenylthiocarbamide (PTC) III. Test U = Thiourea Use the Chi-square stable, which can be found in the Chi-Square Analysis of Mendel's Data page of your online textbook as well as in the Module IV Chi-square analysis lecture, to determine whether you should reject the null hypotheses \( \left(H_{0}\right) \) or not. Provide your answers next to each of the compounds. Sodium benzoate \( \mathrm{Hc}_{\mathrm{c}} \). Phenylthiocarbamide (PTC) \( \mathrm{H}_{0} \) : Thiourea Ho: How do the BIO 340 student results compare to those of previously published data from the USA population? Note: Compare the genotype/allele frequencies of each of the test papers. Did you expect these results? Explain why. Mention 3 reasons why most populations are NoT in Hardy-Weinberg equlibrium: 1. 2. 3. 4.


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Solution: Sodium benzoate H0 = reject null hypothesis Ph
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