(Solved): Below is a perfect thermal radiation curve that was made by spreading out the radiation emitted fro ...

Below is a perfect thermal radiation curve that was made by spreading out the radiation emitted from a solid object at a certain temperature. The wavelengths on the \( x \)-axis are in units of microns \( (\mu \mathrm{m}) \), where \( 1 \mu \mathrm{m}=10^{-6} \) meters. Note that the wavelength of maximum emission \( \lambda(\max ) \) is located at \( 0.5 \mu \mathrm{m} \). What would happen if this object's temperature were doubled? The wavelength of maximum emission would decreaseto \( 0.03125 \mu \mathrm{m} \). The wavelength of maximum emission would decrease to \( 0.0625 \mu \mathrm{m} \). The wavelength of maximum emission would increase to \( 2.0 \mu \mathrm{m} \). The wavelength of maximum emission would increase to \( 1.0 \mu \mathrm{m} \). The wavelength of maximum emission would decrease to \( 0.25 \mu \mathrm{m} \).