Home / Expert Answers / Chemistry / be-sure-to-answer-all-parts-calculate-the-vapor-pressure-of-a-solution-made-by-dissolving-71-9-pa805

(Solved): Be sure to answer all parts. Calculate the vapor pressure of a solution made by dissolving \( 71.9 ...




Be sure to answer all parts.
Calculate the vapor pressure of a solution made by dissolving \( 71.9 \mathrm{~g} \) of urea (mo
Be sure to answer all parts. Calculate the vapor pressure of a solution made by dissolving \( 71.9 \mathrm{~g} \) of urea (molar mass \( =60.06 \mathrm{~g} / \mathrm{mol} \) ) in \( 219.5 \mathrm{~mL} \) of water at \( 35^{\circ} \mathrm{C} \). (Hint: The vapor pressure of pure water at \( 35^{\circ} \mathrm{C} \) is given in the table below. Assume the density of the solution is \( 1.00 \mathrm{~g} / \mathrm{mL} \).) \( \mathrm{mmHg}_{\mathrm{g}} \) What is the magnitude of vapor-pressure lowering? \( \mathrm{mmHg} \)


We have an Answer from Expert

View Expert Answer

Expert Answer


We know , Number of mole=Mass/Molar mass Given , Mass of urea (solute) = 71.9 g Again , Molar mass of Urea (CO(NH2)2) = 60.06 g/mol Then , Number of mole of Urea (solute) = 71.9 g / 60.06 g/mol = 71.9 / 60.06 mol = 1.197 mol We know , Mass = Density
We have an Answer from Expert

Buy This Answer $5

Place Order

We Provide Services Across The Globe