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(Solved): b. h. 2.NaOH11.BH3THF H2O2H2O i. ...

$b. h. \( \frac{\text { 1. } \mathrm{BH}_{3} \cdot \mathrm{THF}}{\text { 2. } \mathrm{NaOH}_{1}} \) \( \mathrm{H}_{2} \mathrm{$

b. h.

\frac{1. BH _{3} ? THF}{2. NaOH _{1}}

H_{2} O_{2} H_{2} O

i

.

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The missing reactant, reagent and the products of the given reaction is shown below

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