(Solved): As the first human astronaut to land on a distant planet, you are standing on the edge of a small cl ...

As the first human astronaut to land on a distant planet, you are standing on the edge of a small cliff. You toss a small experiment apparatus straight up in the air and it reaches a maximum height of 3.0m above the cliff. The apparatus then falls to the bottom of the cliff, landing a distance of 10m below its initial position. The time elapsed between the apparatus being thrown up and landing on the ground was measured to be 5.0s.

What is the average velocity and average speed during this process?

The coordinate system is setup such that "upwards" is +j^? direction.

As the first human astronaut to land on a distant planet, you are standing on the edge of a small cliff. You toss a small experiment apparatus straight up in the air and it reaches a maximum height of \( 3.0 \mathrm{~m} \) above the cliff. The apparatus then falls to the bottom of the cliff, landing a distance of \( 10 \mathrm{~m} \) below its initial position. The time elapsed between the apparatus being thrown up and landing on the ground was measured to be \( 5.0 \mathrm{~s} \). What is the average velocity and average speed during this process? The coordinate system is setup such that "upwards" is in the \( +\hat{j} \) direction. Pick the correct answer - Velocity: \( +2.0 \hat{j} \mathrm{~m} / \mathrm{s} \) Speed: \( 3.2 \mathrm{~m} / \mathrm{s} \) - Velocity: \( 3.2 \mathrm{~m} / \mathrm{s} \) Speed: \( -2.0 j \mathrm{~m} / \mathrm{s} \) Velocity: \( -2.0 \hat{j} \mathrm{~m} / \mathrm{s} \) Speed: \( 2.6 \mathrm{~m} / \mathrm{s} \) Velocity: \( +2.0 \hat{j} \mathrm{~m} / \mathrm{s} \) Speed: \( 2.6 \mathrm{~m} / \mathrm{s} \) Velocity: \( -2.0 \hat{j} \mathrm{~m} / \mathrm{s} \) Speed: \( 3.2 \mathrm{~m} / \mathrm{s} \) Check Your Answer