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(Solved): Answer b and c when molar composition of water is 0.065 and Tdb=190Fpsychrometric chart included Pro ...
Answer b and c when molar composition of water is 0.065 and Tdb=190F
psychrometric chart included
Problem: (30) Air entering a dryer has the following conditions. Give the results with three (3) significant figures. MW: Air (28.86); Water (18.02); \( \mathrm{O}_{2} \) (32.00); \( \mathrm{N}_{2} \) (28.02) Molar composition of water: \( 0.065 \quad \) and \( \quad \mathrm{T}_{\mathrm{db}}: 190^{\circ} \mathrm{F} \) Using the humidity chart, determine: a. Point in the psychrometric chart (3) b. Humid volume; (1) c. Relative humidity: (2)
Figure \( 5.19 \mathrm{a} \) (Reprinted by permission of Camicr Corporation.)
Expert Answer
Data provided Molar composition = 0.065 lb mol H2O / lb mol Air Dry bulb temperature ( Tdb ) = 190 F For 1 lb mol of Air Moles of water = 0.065 lb mol Moles o