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(Solved): An enclosure has an inside area of \( 50 \mathrm{~m}^{2} \), and its inside s ...



An enclosure has an inside area of \( 50 \mathrm{~m}^{2} \), and its inside surface is black and is maintained at a constant ???????

An enclosure has an inside area of \( 50 \mathrm{~m}^{2} \), and its inside surface is black and is maintained at a constant temperature. A small opening in the enclosure has an area of \( 0.01 \mathrm{~m}^{2} \). The radiant power emitted from this opening is \( 52 \mathrm{~W} \). What is the temperature of the interior enclosure wall, in \( \mathrm{K} \) ? If the interior surface is maintained at this temperature, but is now polished so that its emissivity is \( 0.15 \), what will be the value of the radiant power emitted from the opening, in W? \[ \begin{array}{l} T_{s}=\quad \mathrm{K} \\ q_{\mathrm{rad}}=\mathrm{W} \\ \end{array} \]


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Given data: Inside area, A1=50m2 enclosure opening area, A2=0.01m2 radiant power emitted, Q=52W emissivity, ?=0.15 We know that, F21+F22=1 Where, F21=
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