(Solved): Ammonia reacts with oxygen gas to form hitrogen gas according to the fottowing equation: \[ 4 \math ...

Ammonia reacts with oxygen gas to form hitrogen gas according to the fottowing equation: \[ 4 \mathrm{NH}_{3}(g)+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{~N}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(g) \Delta \mathrm{HH}=1267 \mathrm{VJ} \] If \( 97.642 \mathrm{~g} \) of nitrogen are formed, what is the enthalpy change? * Do not round this number (wonite down every digit on calculater \&