(Solved): + Adding Equilibrium Reactions Learning Goal: To understand how to calculate the equilibrium const ...

+ Adding Equilibrium Reactions Learning Goal: To understand how to calculate the equilibrium constants for chemical equations that can be produced by the addition of other chemical equations with known equilibrium constants. For a chemical reaction equation with the general form aA + bB cC+dD the equilibrium equation is given by [C] [D]d [A]ª[B]* K? = Thus, for a chemical reaction equation with the general form cC+dD=eE+fF the equilibrium equation is given by [E] [F] [C] [D]d or K? = If the first two equations are added together such that aA + bB = eE+fF then the equilibrium equation is given by K3 = EF] [A]a[B] _C][D] _E]*F! [A]ª[B] [C] [D] K3 = K? K? Thus, when a chemical equation is the sum of two chemical equations for which equilibrium constants are already known, the equilibrium constant for the reaction is the product of the equilibrium constants for the individual reactions. Keep in mind that equilibrium equations do not include expressions for any pure solids or liquids that may be involved in the reaction. Given the two reactions 1. H?S(aq) HS (aq) +H(aq), K?=9.72x10-8, and 2. HS (aq) S2-(aq) +H+ (aq), K?=1.01x10-19, what is the equilibrium constant Kfinal for the following reaction? Enter your answer numerically. ? View Available Hint(s) Submit Part B V-| ??? xa Xb = ?x vxx x IXI S² (aq) + 2H+ (aq) = H?S(aq) Kfinal 7.94 10-5 You have already submitted this answer. Enter a new answer. No credit lost. Try again. Previous Answers Express your answer numerically. ? View Available Hint/s) X. 10m X Given the two reactions 3. PbCl? (aq) = Pb²+ (aq) + 2Cl(aq), K?=1.89x10-10, and 4. AgCl(aq) = Ag+ (aq) + Cl(aq), K?=1.17x10-4, what is the equilibrium constant Kfinal for the following reaction? ? PbCl? (aq) + 2Ag+ (aq) = 2AgCl(aq) + Pb²+ (aq) Review | Constants I PE