(Solved): A wheel has a constant angular deceleration (negative angular acceleration due to slowing down) of ...

A wheel has a constant angular deceleration (negative angular acceleration due to slowing down) of \( -4.0 \mathrm{rad} / \mathrm{s}^{2} \). The wheel was initially moving at 80 \( \mathrm{rad} / \mathrm{s} \). (a) What is the angular speed of the wheel at \( \mathrm{t}=12 \mathrm{~s} \) ? (b) How many revolutions did the wheel make during \( 6.0 \mathrm{~s} \) ? Equations: (a) \( \omega=\omega_{0}+\alpha t \) (b) \( \theta=\omega_{o} t+\frac{1}{2} \alpha t^{2} \quad \) then divide the answer by \( 2 \pi \) (a) \( 60 \mathrm{rad} / \mathrm{s} \) (b) 215 revolutions (a) \( 16 \mathrm{rad} / \mathrm{s} \) (b) 75 revolutions (a) \( 68 \mathrm{rad} / \mathrm{s} \) (b) 51 revolutions (a) \( 80 \mathrm{rad} / \mathrm{s} \) (b) 103 revolutions (a) \( 32 \mathrm{rad} / \mathrm{s} \) (b) 65 revolutions