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(Solved): A Water Balloon Battle. You are launching water balloons at a rival team using a large slingshot. T ...




A Water Balloon Battle. You are launching water balloons at a rival team using a large slingshot. The other team is set up on
A Water Balloon Battle. You are launching water balloons at a rival team using a large slingshot. The other team is set up on the opposite side of a flat-topped building that is \( 30.0 \mathrm{ft} \) tall and \( 50.0 \mathrm{ft} \) wide. Your reconnaissance team has reported that the opposition is set up \( 10.0 \mathrm{~m} \) from the wall of the building. Your balloon launcher is calibrated for launch speeds that can reach as high as \( 120 \mathrm{mph} \) at angles between 0 and \( 85.0^{\circ} \) from the horizontal. Since a direct shot is not possible (the opposing team is on the opposite side of the buildingl. you plan to splash the other team by making a balloon explode on the ground near them. If your launcher is located \( 55.0 \mathrm{~m} \) from the building (opposite side as the opposing team), what should your launch velocity be ((a) magnitude and (b) direction) to land a balloon \( 5.0 \) meters beyond the opposing team with maximum impact (i.e. maximum vertical speed)? (a) Number Units (b) Number Units


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The maximum launch velocity for the balloons is 120 mph, therefore Vmax = 100 mph = 53.645 m/s The range of the projectile is estimated as given i
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