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(Solved): A very long, straight horizontal wire carries a current such that \( 8.15 \times 10^{18} \) Part A ...



A very long, straight horizontal wire carries a current such that \( 8.15 \times 10^{18} \)
Part A
electrons per second pass

A very long, straight horizontal wire carries a current such that \( 8.15 \times 10^{18} \) Part A electrons per second pass any given point going from west to east. What is the magnitude of the magnetic field this wire produces at a point \( 4.70 \mathrm{~cm} \) directly above it? Express your answer with the appropriate units. Part B What is the direction of the magnetic field?


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Answer: • B = 5.55 × 10?? T • to the South Explanation: The given wire has a flow of electrons 8.15 × 10¹? /s we have, i = n
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