(Solved): A telephone line hangs between two poles 14m apart in the shape of the catenary y=15cosh(15x) ...

A telephone line hangs between two poles $14\mathrm{m}$ apart in the shape of the catenary $y=15\cosh \left(\frac{x}{15}\right)?10$, where $x$ and $y$ are measured in meters. (a) Find the slope of this curve where it meets the right-hand pole. (Round your answer to four decimal places.) (b) Find the angle $?$ (in degrees) between the line and the pole. (Round your answer to two decimal places.) $?=$