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(Solved): A survey of 25 tetal stores revealed that the average price of an ake fryer was \( \$ 45 \) with a ...




A survey of 25 tetal stores revealed that the average price of an ake fryer was \( \$ 45 \) with a sample standard deviation
A survey of 25 tetal stores revealed that the average price of an ake fryer was \( \$ 45 \) with a sample standard deviation of \( \$ 20 \). Assuming the population is namally distributed. Conatruct the \( 99 \% \) interval estimate of the true peice of an air tryer. \[ \begin{array}{l} (33.6,56.2) \\ (37.252 .8) \\ (3.7,55.3) \\ (35.7,54.3) \end{array} \] quistion 13 16 be \( (T 00,1300) \) How aheild we imerpret tha? There is a \( 9 \% \) chance that the actial average rental price of a 1 bedroom apatment in Morgantown lies in the interval (roo, i300) The the value of average tental price we be somewhere tetween 700 and 1300 Since this wat rot based on populwton stantand deviafon, the interpretasion is undear


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Solution : Given Data : Sample size = n = 25 Sample mean = X? = 45 Sample Standard deviation = s = 20 Confidence le
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