A spar buoy is a rod weighted to float vertically, as shown in the image. Let the buoy be maple wood $(SG = 0.6), 2$ inches by 2 inches by 10 feet, floating in seawater $(SG = 1.025)$ . How many pounds of steel $(SG = 7.85)$ should be added at the bottom so that $h = 16$ in?

Question

A spar buoy is a rod weighted to float vertically, as shown in the image. Let the buoy be maple wood

(SG = 0.6), 2

inches by 2 inches by 10 feet, floating in seawater

(SG = 1.025)

. How many pounds of steel

(SG = 7.85)

should be added at the bottom so that

h = 16

in?

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