(Solved): A solution is prepared by dissolving 20.2 mL of methanol (CH3OH, molar mass =32 g/mol) in 100.0 ...

A solution is prepared by dissolving 20.2 $\mathrm{mL}$ of methanol $({\mathrm{CH}}_3\mathrm{OH}$, molar mass $=32$ $\mathrm{g}/\mathrm{mol})$ in $100.0\mathrm{mL}$ of water $({\mathrm{H}}_2\mathrm{O}$, molar mass $=18\mathrm{g}/\mathrm{mol}$ ) at $25^{?}\mathrm{C}$. The final volume of the solution is $118\mathrm{mL}$. The densities of methanol and water at this temperature are $0.782\mathrm{g}/\mathrm{mL}$ and 1.00 $\mathrm{g}/\mathrm{mL}$, respectively. Calculate the molality $(\mathbf{m})$ of this solution. Enter your answer to the second decimal place and do not round until the final answer.