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(Solved): A solenoidal coil with 30 turns of wire is wound tightly around another coil with 300 turns. The inn ...
A solenoidal coil with 30 turns of wire is wound tightly around another coil with 300 turns. The inner solenoid is 25.0 cmcm long and has a diameter of 2.00 cmcm. At a certain time, the current in the inner solenoid is 0.140 AA and is increasing at a rate of 1600 A/sA/s.
A solenoidal coil with 30 turns of wire is wound tightly around another coil with 300 turns. The inner solenoid is long and has a diameter of . At a certain time, the current in the inner solenoid is and is increasing at a rate of . For this time, calculate the average magnetic flux through each turn of the inner solenoid. Express your answer in webers. N Incorrect; Try Again; 4 attempts remaining
For this time, calculate the mutual inductance of the two solenoids. Express your answer in henries. Part C For this time, calculate the emf induced in the outer solenoid by the changing current in the inner solenoid. Express your answer in volts.
Expert Answer
Given data is listed belowNumber of turns in inner solenoid = N1 = 300Number of turns in outer solenoid = N2 = 30 Length of the inner solenoid L= 25cm = 0.25mRadius of inner solenoid r = d/2 = 2/2 =1cm =0.01mThe current in the inner solenoid is I =0.140ARate of increasing of current = di/dt = 1600A/s The average magnetic flux through each turn of the inner solenoid. =B.A