(Solved): A scientist measures the standard enthalpy change for the following reaction to be \( -99.6 \mathr ...

A scientist measures the standard enthalpy change for the following reaction to be \( -99.6 \mathrm{~kJ} \) : \[ 4 \mathrm{HCl}(g)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(g)+2 \mathrm{Cl}_{2}(g) \] Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of \( \operatorname{HCl}(g) \) is \( \mathrm{kJ} / \mathrm{mol} \) \[ \mathrm{CaCO}_{3}(s) \rightarrow \mathrm{CaO}(s)+\mathrm{CO}_{2}(g) \] Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of \( \mathrm{CO}_{2}(g) \) is \( \mathrm{kJ} / \mathrm{mol} \). \[ \mathrm{CO}_{2}(g)+\mathrm{H}_{2}(g) \rightarrow \mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \] Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of \( \mathrm{CO}(g) \) is \( \mathrm{kJ} / \mathrm{mol} \).