(Solved): A rock is thrown upward from a bridge that is 38 feet above a road. The rock reaches its maximum h ...

A rock is thrown upward from a bridge that is 38 feet above a road. The rock reaches its maximum height above the road 0.99 seconds after it $i$ thrown and contacts the road 2.63 seconds after it was thrown. Write a function $f$ that determines the rock's height above the road (in feet) in terms of the number of seconds $t$ since the rock was thrown. $f(t)=$ Helpful Hints: (1). Draw a picture of $f$ by hand. Recall that the axis of symmetry goes through the vertex. The zeros of $f$ are both the same distance from the axis of symmetry. You can use this to find the second zero of $f$. (2). The function $f$ can be written in factored form $f(t)=c?\left(t?t_1\right)\left(t?t_2\right)$ for fixed numbers $c,t_1$, and $t_2$.