(Solved): A neutron in a nuclear reactor makes an elastic, head-on collision with the nucleus of a carbon ato ...

A neutron in a nuclear reactor makes an elastic, head-on collision with the nucleus of a carbon atom initially at rest. (a) What fraction of the neutron's kinetic energy is transferred to the carbon nucieus? (The mass of the carbon nucleus is about 12.0 times the mass of the neutron.) (b) The initial kinetic energy af the neutron is $1.90\times 10^{?11}$.. Find its final kinetic energy and the kinetic energy af the carbon nucleus after the collision. nevtron $x$, carbon nudeus 3 An unstable atomic nucleus of mast $1.54\times 10^{?215}\mathrm{kg}$ irtitially at rest disintegrates into three particles, One of the particies, of mass $5.14\times 10^{?27}\mathrm{kg}$, moves in the $y$ direction with a speed of $6.00\times 10^6\mathrm{m}/\mathrm{s}$. Another particle, of mass $0.50\times 10^{?27}\mathrm{kg},\mathrm{moves}$ in the $x$ direction with a speed of $4.00\times 10^6\mathrm{m}/\mathrm{s}$. (a) Find the velocity of the third particle $(1+1\mathrm{d})m/s$ (b) Find the total kinetic energy increase in the process. 3 When human skin is wounded because of a puncture or serape, disk-shaped keratinocyte cells migrate to the wound to form a first barrier against infection of the wound. Keratinocyte cells, typically $10.0\mathrm{jm}$ in diameter, have been shown to reach the wound site by rolling along the topmost layer of exposed skin at an angular speed of $2.50\mathrm{r}\mathrm{rad}/\mathrm{h}$. (a) If keratinocyte celis migrate from boch ends of a $3.30\mathrm{mm}$-long scrape, how long (in hours) would it take the celis to form a complete barrier? hours (b) What is the transtational kinetic energy (in 3 ) of a single keratinocyte cell with a mass of $2.00\times 10^{?9}9$ as it rolis toward a wound site? 1 (c) What is the rotational kinetic energy (in $J$ ) of a single keratinocyte cell with a mass of $2.00\times 10^{?9}9$ as it rolls toward a wound site? 3