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(Solved): A Lathe rotating at \( 200 \mathrm{rpm} \) is used to reduce the diameter of an \( 10 \mathrm{~cm} ...




A Lathe rotating at \( 200 \mathrm{rpm} \) is used to reduce the diameter of an \( 10 \mathrm{~cm} \) long section of stock m
A Lathe rotating at \( 200 \mathrm{rpm} \) is used to reduce the diameter of an \( 10 \mathrm{~cm} \) long section of stock metal rod from a diameter of \( 99 \mathrm{~mm} \) to \( 95 \mathrm{~mm} \) at a feed rate of \( 3.1 \mathrm{~mm} / \mathrm{rev} \). The force measured at the tool post was \( 3300 \mathrm{~N} \) down and \( 1700 \mathrm{~N} \) pulling the tool toward the workpart. What is the specific energy of this material? \( \mathrm{U}= \) \( \mathrm{J} / \mathrm{mm}^{3} \)


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FROM THE FIGURE , IT CAN BE CONCLUDED THAT IT IS AN ORTHOGONAL CUTTING. In othogonal cutting: Width of uncut chip = Depth of cut =99mm-95mm = 4mm
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