(Solved): A homogeneous mixture, \( 600.00 \mathrm{~mL} \) in volume, is \( 40.00 \) grams in sodium hydroxi ...

A homogeneous mixture, \( 600.00 \mathrm{~mL} \) in volume, is \( 40.00 \) grams in sodium hydroxide \( (\mathrm{NaOH} \), molar mass \( =40 \mathrm{~g} / \mathrm{mol}) \) and \( 562.00 \) grams in water \( \left(\mathrm{H}_{2} \mathrm{O}\right. \), molar mass \( =18 \) \( \mathrm{g} / \mathrm{mol}) \). Perform the calculations. Write the the answers on paper. Show all work. Scan and upload the file. 1. What is the mass percent of \( \mathrm{NaOH} \) ? The formula is \[ \text { mass } \% \mathrm{NaOH}=\frac{\text { mass of } \mathrm{NaOH}}{\text { (mass of } \mathrm{NaOH}+\text { mass of } \mathrm{H} 2 \mathrm{O})} x 100 \] 2. How many moles of \( \mathrm{NaOH} \) are there? The formula is moles of \( \mathrm{NaOH}=\frac{\text { mass of } \mathrm{NaOH}}{\text { molar mass of } \mathrm{NaOH}} \) 3. How many moles of \( \mathrm{H}_{2} \mathrm{O} \) are there? The formula is moles of \( \mathrm{H}_{2} \mathrm{O}=\frac{\text { mass of } \mathrm{H}_{2} \mathrm{O}}{\text { molar mass of } \mathrm{H} 2 \mathrm{O}} \) 4. What is the solution's molarity? The formula is molarity \( =\frac{\text { moles of } \mathrm{NaOH}}{\text { liters of solution }} \) 5. What is the solution's osmolarity? The formula is Osmolarity \( = \) Molarity \( x(\# \) particles \( / \) compound \( ) \) The dissociation of \( \mathrm{NaOH} \) in water is: \[ \mathrm{NaOH}(\mathrm{s}) \underset{\mathrm{H}_{2} \mathrm{O}}{\longrightarrow} \mathrm{Na}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) \] 6. What is the solution's molality? The formula is \[ \text { molality }=\frac{\text { moles of } \mathrm{NaOH}}{\mathrm{kg} \text { of } \mathrm{H}_{2} \mathrm{O}} \] 7. What is the solution's osmolality? The formula is Osmolality \( = \) Molality \( x(\# \) particles \( / \) compound \( ) \) 8. What is the mole fraction of \( \mathrm{H}_{2} \mathrm{O} \) ? The formula is \[ \chi=\frac{\mathrm{mol} \mathrm{H}_{2} \mathrm{O}}{\left(\mathrm{mol} \mathrm{H}_{2} \mathrm{O}+\mathrm{mol} \mathrm{NaOH}\right)} \]