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(Solved): A double tube counterflow heat exchanger is used to cool a hot liquid stream of biodiesel from 60C ...



A double tube counterflow heat exchanger is used to cool a hot liquid stream of biodiesel from 60°C to 35°C. Biodiesel flows on the annular section side with a volumetric flow rate of 3 m3/h, water is used on the tube side. The inlet and outlet temperatures for the cooling water flow are 10°C and 30°C. respectively. The inner tube is 1.5-inch schedule 80 copper material. In independent experiments, it will be found that the heat transfer coefficient for biodiesel on the annular section side was 340 W/m2.K
Calculator:
a) How is the heat transfer guaranteed in the given problem?
b) What is the heat load on the heat exchanger?
c) What is the mass velocity of cooling water required?
d) What is the required surface area of the heat exchanger?

\( N u=\frac{\frac{f}{2} \cdot(N r e-1000) \cdot N p r}{1+12.7 \sqrt{\frac{f}{2}} \cdot\left[\sqrt[3]{N p r^{2}}-1\right]} \q???????

\( N u=\frac{\frac{f}{2} \cdot(N r e-1000) \cdot N p r}{1+12.7 \sqrt{\frac{f}{2}} \cdot\left[\sqrt[3]{N p r^{2}}-1\right]} \quad \quad f=0.25\left(1.82 \log _{i 0} \text { Nre }-1.64\right)^{-2} \) \( N u=\frac{h \cdot D}{k} \quad N r e=\frac{D \times v \times r}{m} \quad N p r=\frac{C p m}{k} \)


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(a) Heat transfer is possible only if LMTD is non zero (if it's is zero no temperature difference for heat transfer) so we will calculate LMTD LMTD = (T1 -T2)/ln (T1/T2) T1 - Temperature difference at inlet (that is difference in temperature between
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