(Solved): (a) Determine the position x(t) of the object at the following times. t=0.0,3.00s,9.00s,and ...

(a) Determine the position $x(t)$ of the object at the following times. $t=0.0,3.00\mathrm{s},9.00\mathrm{s}\text{, and }18.0\mathrm{s}$ $x(t=0)=$ Values for the position of the object at any time may be read directly from the plot of position versus time. $m$ $x(t=3.00$ x $s)=$ Values for the position of the object at any time may be read directly from the plot of position versus time. $m$ $x(t=9.00$ s) Values for the position of the object at any time may be read directly from the plot of position versus time. $m$ (b) Determine the displacement $?x$ of the object for the following time intervals. (Indicate the direction with the sign of your answer.) $\begin{array}{l}?t=(0?6.00\mathrm{s}),(6.00\mathrm{s}?12.0\mathrm{s}),(12.0\mathrm{s}?18.0\mathrm{s})\text{, and }(0?18.0\mathrm{s})\\ ?x(0?6.00\mathrm{s})=\text{ Review the definition of displacement, }\mathrm{m}\\ ?x(6.00\mathrm{s}?12.0\mathrm{s})=\\ ?x(12.0\mathrm{s}?18.0\mathrm{s})=\frac{\mathrm{R}}{\text{ Review the definition of displacement, }\mathrm{m}}\\ ?\times (0?18.00\mathrm{s})=\frac{\mathrm{X}}{\text{ Review the definition of displacement, }\mathrm{m}}\end{array}$ Review the definition of displacement. $m$ (c) Determine the distance $d$ traveled by the object during the following time intervals. $?t=(0?6.00\mathrm{s}),(6.00\mathrm{s}?12.0\mathrm{s}),(12.0\mathrm{s}?18.0\mathrm{s})\text{, and }(0?18.0\mathrm{s})$ $d(0?6.00\mathrm{s})=$ How is the distance traveled by the object during a time interval related to the displacement the object during this same time interval? $\mathrm{m}$ $d(6.00\mathrm{s}?=$ $d(12.0\mathrm{s}?\overrightarrow{\mathrm{s}})$ = How is the distance traveled by the object during a time interval related to the displacement the object during this same time interval? $m$ x $d(0?18.0\mathrm{s})=$ If you know the distance traveled for each time interval of a tpip, how can you determine the distance traveled for the entire trip? $m$ (d) Determine the average velocity ${\vec{v}}_{\text{velocity }}$ of the object during the following time intervals. $\begin{array}{l}?t=(0?6.00\mathrm{s}),(6.00\mathrm{s}?12.0\mathrm{s}),(12.0\mathrm{s}?18.0\mathrm{s})\text{, and }(0?18.0\mathrm{s})\\ {\stackrel{?}{v}}_{\text{velocity }}(0?6.00\mathrm{s})={}_{\text{Review the definition of average velocity. }\mathrm{m}/\mathrm{s}}\\ {\stackrel{?}{v}}_{\text{velocity }}(6.00\mathrm{s}?12.0\mathrm{s})=\\ {\stackrel{?}{v}}_{\text{velocity }}(12.0\mathrm{s}?18.0\mathrm{s})=\frac{\mathrm{m}/\mathrm{s}}{\text{ Review the definition of average velocty, }\mathrm{m}/\mathrm{s}}\\ {\stackrel{?}{v}}_{\text{velocty }}(0?18.0\mathrm{s})=\text{ Review the definition of average velocity. }\mathrm{m}/\mathrm{s}\end{array}$ (e) Determine the average speed ${\stackrel{?}{v}}_{\text{speed }}$ of the object during the following time intervals. $\begin{array}{l}\begin{array}{l}{\stackrel{?}{v}}_{\text{speed }}(6.00\mathrm{s}?12.0\mathrm{s})=\\ {\stackrel{?}{v}}_{\text{speed }}(12.0\mathrm{s}?18.0\mathrm{s})=\text{ Review the definition of average speed. }\mathrm{m}/\mathrm{s}\end{array}\\ {\vec{V}}_{\text{speed }}(0?18.05)=\frac{}{\text{ Review the definition of average speed. }\mathrm{m}/\mathrm{s}}\end{array}$