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(Solved): A brass (nonmagnetic) block \( A \) and a steel magnet \( B \) are in equilibrium in a brass tube ...



A brass (nonmagnetic) block \( A \) and a steel magnet \( B \) are in equilibrium in a brass tube under the magnetic repellin

A brass (nonmagnetic) block \( A \) and a steel magnet \( B \) are in equilibrium in a brass tube under the magnetic repelling force of another steel magnet \( C \) located at a distance \( x=0.0056 \mathrm{~m} \) from \( B \). The force is inversely proportional to the square of the distance between \( B \) and \( C \). If block \( A \) is suddenly removed, the acceleration of block \( B \) is \( a=-9.81+k / x^{2} \), where \( a \) and \( x \) are expressed in \( \mathrm{m} / \mathrm{s}^{2} \) and meters, respectively, and \( k=4 \times 10^{-4} \mathrm{~m}^{3} / \mathrm{s}^{2} \). Determine the maximum velocity and acceleration of \( B \). The maximum velocity is \( \mathrm{mm} / \mathrm{s} \uparrow \). The maximum acceleration is \( \quad \mathrm{m} / \mathrm{s}^{2} \uparrow \).


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To determine the maximum velocity and acceleration of block B, we need to integrate the equation of motion for block B, which is given by ² a=?9.81+kx
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