(Solved): A bowling ball is rolling smoothly with a speed of \( v_{o}=28.4 \mathrm{n} \ ...

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A bowling ball is rolling smoothly with a speed of \( v_{o}=28.4 \mathrm{n} \) horizontal surface. It then rolls up a ramp to a height of \( h=6.4 \) and continues moving. Calculi: inal speed \( v_{f} \). Take the moment of inertia of the ball as \( I=0.8 \mathrm{mR}^{2} \). Please round your answer to \( \mathrm{c} \) mal place. Equation: \[ \begin{array}{c} v_{o}^{2}+\frac{1}{2} I \omega_{o}^{2}=\frac{1}{2} m v_{f}^{2}+\frac{1}{2} I \omega_{f}^{2}+m g h \\ \omega_{o}^{2}=\frac{v_{o}^{2}}{R^{2}} \quad \omega_{f}^{2}=\frac{v_{f}^{2}}{R^{2}} \end{array} \]