(Solved): A 5.375-ft square, 2.0-ft deep spread footing is subjected to a concentric vertical load of 66.0k a ...

A 5.375-ft square, 2.0-ft deep spread footing is subjected to a concentric vertical load of $$66.0\mathrm{k}$$ and an overturning moment of $$30.0\mathrm{ft}?\mathrm{k}$$. The overturning moment acts parallel to one of the sides of the footing, and the top of the footing is flush with the ground surface and the groundwater table is at a depth of $$1.5\mathrm{ft}$$ below the ground surface. Determine whether the resultant force acts within the middle third of the footing, compute the minimum and maximum bearing pressures and show the distribution of bearing pressure in a sketch. Determine the size of the equivalent uniformly loaded footing and compute the equivalent bearing pressure. Solution: 1. Preliminary calculation: 1). Area of the footing: $$A=$$ 2). Self weight of the footing: $$W_f=$$ Ib; 3). Pore water pressure at the bottom of the footing due to ground water: $$\mathrm{u}=$$ 2. Check eccentricity: 1). Eccentricity of bearing pressure distribution: $$e=$$ $$\mathrm{ft}$$ 2). Middle third of the footing: $$B/6=\mathrm{ft}$$; 3). Thus the bearing pressure distribution is 3. Caiculate the minimum and maximum bearing pressure: 2. Check eccentricity: 1). Eccentricity of bearing pressure distribution: $$e=$$ 2). Middle third of the footing: $$B/6=$$ $$\mathrm{ft}$$; 3). Thus the bearing pressure distribution is 3. Calculate the minimum and maximum bearing pressure: 1). $$q_{\min }=$$ 2). $$q_{\max }=$$ 4. Equivalent uniformly loaded fq?coting: 1). Eequivalent uniformly loaded footing width: $$B^{?}=$$ 2). Eequivalent bearing pressure: $$q_{cq}=\mathrm{kips}/\mathrm{tt}$$ ?