(Solved): A. 305km-lang high woltage transmission line 2.0cm in diameter carries a steady current of 1,00 ...

A. $$305\mathrm{km}$$-lang high woltage transmission line $$2.0\mathrm{cm}$$ in diameter carries a steady current of $$1,005\mathrm{A}$$. If the conductor is copper with a free charge density of $$8.5\times 10^{28}$$ electrons per cuble meter, bow many years does it take ane electron to travel the full length of the cable? Step 1 The deit speed of charge carriers in a conductor carrying current $$f$$ is $$y_d=\frac{t}{n?A}$$ where $$n$$ is the number of mobile charge carriers per unit volume, $$q$$ is the magnitude of the charge on each carrier, and A is the cross-sectional area of the conductor. The transmission. line bas a diameter of $$2.0\mathrm{cm}$$ so that its radius is $$r=1.0\mathrm{cm}=1.0\times 10^{?2}\mathrm{m}$$ and so that its cross-sectionsl area is $$A=?r^2=?{\left(1.0\times 10^{?2}\mathrm{m}\right)}^2=?\times 10^{?4}{\mathrm{m}}^2$$ In metalic conductors, the mobile charge camers are efectrons, each with a charge of magnitude $$q=e$$. We are given the density of free electrons in this copper material per unit velume. Thus, the drif speed of the electrons is $$\begin{array}{l}{v}_j=\frac{1}{n{q}^A}\\ ?2.55?10^{?4}\mathrm{m}/\mathrm{s}.\end{array}$$ The time at that the ekecrom require to dritt the lengegh 2 of the cabie is $$\text{ St }=\frac{1}{4?}=\text{ Your ressonte is off tiy a munpie of ten, }\times 10^2\mathrm{m})\left(\frac{1\text{ yr }}{3.156\times 10^{?}\mathrm{s}}\right)=$$