(Solved): 9) The normal sequence of 9 genes along a chromosome is \( \mathrm{ABCD} \cdot \mathrm{EFGHI} \) ( ...

9) The normal sequence of 9 genes along a chromosome is \( \mathrm{ABCD} \cdot \mathrm{EFGHI} \) (where \( \cdot \) represents the centromere). A person is found to be an inversion heterozygote, with one normal copy of this chromosome, and another with the sequence AFE \( \cdot \) DCBGHI. A single crossover event occurs during meiosis between two non-sister chromatids in the segment between the \( \mathrm{C} \) and \( \mathrm{D} \) genes. What products could result from this crossover event to produce gametes that were NOT viable? A) \( \mathrm{ABCD} \cdot \mathrm{EFA} \) and IHGFE \( \cdot \mathrm{DCBGHI} \) B) ABCDCBGHI and IHGFE \( \cdot D \cdot E F A \) C) \( \mathrm{ABCCBGHI} \) and IHGFE \( \cdot \mathrm{DD} \cdot \mathrm{EFA} \) D) \( \mathrm{ABCD} \cdot \mathrm{EFBA} \) and \( \mathrm{IHGFE} \cdot \mathrm{DCGHI} \)