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(Solved): 8. The equation for the combustion of gaseous propanol is \[ \begin{array}{cccc} & 2 \mathrm{CH}_{3 ...




8. The equation for the combustion of gaseous propanol is
\[
\begin{array}{cccc} 
& 2 \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm
8. The equation for the combustion of gaseous propanol is \[ \begin{array}{cccc} & 2 \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}(\mathrm{g})+9 \mathrm{O}_{2}(\mathrm{~g}) & \longrightarrow & \mathrm{CO}_{2}(\mathrm{~g})+8 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \\ \Delta \mathrm{H}^{\circ}(\mathrm{kJ} / \mathrm{mol}) \quad & -255 & -393.5 & -241.8 \end{array} \] Use bond energies to estimate the energy change for the reaction. What is the heat of combustion of one mole of gaseous propanol? Compare your answer using bond energies with a calculation of the change in enthalpy using \( \Delta H_{i}{ }^{\circ} \) values.


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