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(Solved): 7) Circularly Singly Linked List - Tracing [9 points] Given the sample class (implementation omitte ...
7) Circularly Singly Linked List - Tracing [9 points] Given the sample class (implementation omitted) trace the recursive circularly singly linked list method mystery, and fill in the table accordingly. After filling in the table, fill in the linked list at the bottom with the final state of the CSLL. The value returned to is not important, do not write it. For clarification, the first line of the table has been filled in for you. public class doMystery \{ private class Node \{ //implementation omitted ? private Node head; public int mystery(Node curr, int temp) \{ if (curr. equals(head)) \{ return temp; \} if (curr. data \% ) \{ curr.next.data = mystery (curr. next. next, temp +1; return temp +1 ; ? curr. data = mystery curr. next, temp +1; return temp - 1 ; \} \} int mystery head. next, 7; // TABLE AND BLANK LINKED LIST ON FOLLOWING PAGE
Fill in the table according to the labeled columns. For clarification, the first line has been filled in for you. If no index is modified, or any other column does not need a value, leave the box blank, or write an . The Current Temp column should be filled with the value of the second input parameter named temp of the mystery method. Notes: - If the executed line is curr. data , the index to modify will match the current index. - If the executed line is curr. next. data , the index to modify will be current index +1 Fill in the final state of the Linked List below:
Expert Answer
To trace the recursive circularly singly linked list method mystery, we will follow the provided code and fill in the table accordingly. Here's the initial state of the table:ow, let's go through each step of the mystery method and update the table accordingly:Since curr (head.next) is not equal to head, we move to the next step.The data in the current node (curr.data) is odd, so we skip the if condition and move to the next step.The current node's data is odd, so we call mystery recursively with curr.next and temp + 1 as arguments. The returned value is not important, so we skip it for now and move to the next step.We return temp + 1, which means the updated value of temp is 8.We assign the returned value (8) to the current node's data (curr.data).We return the result of another recursive call to mystery with curr.next and temp + 1 as arguments. The returned value is not important, so we skip it for now and move to the next step.We return temp - 1, which means the updated value of temp is 7.We assign the returned value (7) to the current node's data (curr.data).Since curr (head.next) is not equal to head, we move to the next step.The data in the current node (curr.data) is odd, so we skip the if condition and move to the next step.The current node's data is odd, so we call mystery recursively with curr.next and temp + 1 as arguments. The returned value is not important, so we skip it for now and move to the next step.We return temp + 1, which means the updated value of temp is 8.We assign the returned value (8) to the current node's data (curr.data).We return the result of another recursive call to mystery with curr.next and temp + 1 as arguments. The returned value is not important, so we skip it for now and move to the next step.We return temp - 1, which means the updated value of temp is 7.We assign the returned value (7) to the current node's data (curr.data).Since curr (head.next) is equal to head, we return the value of temp, which is 7.The final state of the table:Finally, based on the updated values in the table, we can construct the linked list with the final state: