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(Solved): 5) Please help me solve the 7 parts. I attached example question For the cross-tabulation data show ...



5) Please help me solve the 7 parts. I attached example question

For the cross-tabulation data shown below, which represents a count of the type of books that individuals prefer, verify that
or the cross-tabulation data shown below, which represents a count of the type of books that individuals prefer, verily that
For the cross-tabulation data shown below, which represents a count of the type of books that lindividuals prefer, verify tha


For the cross-tabulation data shown below, which represents a count of the type of books that individaals prefer, verify that
For the cross-tabulation data shown below, which represents a count of the type of books that individuals prefer, verify that the assuimptions of the chi-square test are not met, an agrregate the data in an apprapriale way so that the assumptions are met. Then conduct a chi square fest for independence at the \( 0.05 \) lawel of significance First, verily that the assumptions are nof met Determine which sets of data to group together, and ceate the new, agregated data table. (Type whole numbers] Next, wilte the hypothesen for the chis square test for independence or the cross-tabulation data shown below, which represents a count of the type of books that individuals prefer, verily that the assumptions of the chi-square test are not met, and zgregate the data in an appropriate way so that the assumptions are met. Then conduct a chi-square test for independence at the 0 . 05 level of significance. Type infegers or docimals rounded to two decimas pares as neveru, Compute the chi-square statistic \( 0.42 \) (Type an inseger or decimal rounded to two decimal places as needed.) Find the p-value and draw a conclusion. \( p \)-value \( =0.516 \) (Type an integer or decimal rounded to three decimal places as needed.) The p.value is greater than the level of significance of \( 0.05 \). Therefore, fat to reject the nuill hypothesis and conclude that Gender and Book Preference are For the cross-tabulation data shown below, which represents a count of the type of books that lindividuals prefer, verify that the assumptions of the chi square test are not met, and aggregate the data in an appropriate way so that the assumptions are met. Then conduct a chi-square test for independence at the \( 0.05 \) level of signilicanch First, verity that the assumptions are not met. \( 20 \% \) of cells have expected frequenciess smaller than 5 . There expected frequencies of zero. Therefore, the assumptions Determine which sets of data to group together, and create the now, aggregated data table. For the cross-tabulation data shown below, which represents a count of the type of books that individaals prefer, verify that the assumptions of the chil square teist ase not enet, and aggregate the data in ant approprlate way so that the assumptions are mot. Then conduct a chi-square test for independence at the 0 . 05 level of sigrificance: First, verity that the assumptions are not met \( 20 \% \) of cells have expected frequencies smaller than 5 . There expected trequoncies of zero. Therelore, the ansumptions Determine which sets of data to group together, and create the new, aggregated data table.


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Given, The data table of the gender and preferred book is: Gender Fiction Nonfiction Romance Autobiograp
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