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(Solved): 4. Label the reactant of the acid/base reaction with acid, conjugate acid, base, and conjugate base ...




4. Label the reactant of the acid/base reaction with acid, conjugate acid, base, and conjugate base, fill in the missing pKa,
4. Label the reactant of the acid/base reaction with acid, conjugate acid, base, and conjugate base, fill in the missing pKa, and indicate whether the reaction will mostly proceed to the left or right ( 2 points): \( \mathrm{pKa}= \) (fill in) buse 5. Draw in all missing lone pairs and calculate the formal charge for the atoms in the molecule below ( 1 point):


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4. Whether equilibrium lies to right side or left side depends upon acidity of the reactant and product. if reactant is more acidic than product, then equilibrium lies completely to the right side. if product is more acidic than reactant then equili
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