37. A 1.35 molal aqueous solution of compound X had a boiling point of 101.4 °C. Which one of the following could be compound X? The boiling point elevation constant of water is 0.52 °C m¯¹. A BUDE A. B. C. D. E. CH3CH?OH C6H12O6 Na3PO4 CaCl? KCl ??? = kb x mxi i= ? - ??? kbym 101 1133 = 1414 =

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37. A 1.35 molal aqueous solution of compound

X

had a boiling point of

101. 4^{?} C

. Which one of the following could be compound

X

? The boiling point elevation constant of water is

0.5 2^{?} C m^{? 1}

. A.

CH_{3} CH_{2} OH

? T b = kb \times m \times i

B.

C_{6} H_{12} O_{6}

C.

Na_{3} PO_{4}

D.

CaCl_{2}

i = \frac{? T b}{kb r m} = \frac{101}{1 , 30} = 142

E.

KCl

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Expert Answer to - 37. A 1.35 molal aqueous solution of compound X had a boiling point of 101.4 C. Which one of the f

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Solution for - 37. A 1.35 molal aqueous solution of compound X had a boiling point of 101.4 C. Which one of the f

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This an additional answer to - 37. A 1.35 molal aqueous solution of compound X had a boiling point of 101.4 C. Which one of the f

(Solved): 37. A 1.35 molal aqueous solution of compound X had a boiling point of 101.4 C. Which one of the f ...

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