(Solved): ") Compute the value of the following improper integral. If it converges, enter its value. Enter i ...

") Compute the value of the following improper integral. If it converges, enter its value. Enter infinity if it diverges to \( \infty \), and -infinity if it diverges to \( -\infty \). Otherwise, enter diverges. \[ \int_{1}^{\infty} \frac{3 d x}{x^{2}+1}= \] Does the series \( \sum_{n=1}^{\infty} \frac{3}{n^{2}+1} \) converge or diverge?