3. Show that y, = sin x² and y? = cos x² are linearly independent functions, but that their Wronskian vanishes at x=0. Why does this imply that there is no differential equation of the form y" + p(x)y'+q(x)y=0, with both p and q continuous everywhere, having both y, and Y? as solutions? Two functions defined on an open interval I are said to be linearly independent on I provided that (1) Y? The functions y, = sin x² and y? = cos x² are linearly independent because Y2 function and = (3) Y1 (Type expressions using x as the variable.) Given two functions f and g, the Wronskian off and g is the determinant defined as follows. W(f.g) = (4) The Wronskian for these functions, W(sinx, cos x²)=[ (Type an expression using x as the variable.) (4) (1) the two functions are not identical on 1. neither is a constant multiple of the other. Why does this imply that there is no differential equation of the form y+p(xly + g(x)y= 0, with both p and q continuous everywhere, having both y, and y2 as solutions? OA Such an equation would require that the Wronskian is nonzero for every point on the real line Since W (sin x² cos x)=0 for x=0, such an equation cannot exist. LOG 00 OB. Such an equation would require that the Wronskian is nonzero for at most one point on the real line. Since W (sin x², cos x²) #0 for any x #0, such an equation cannot exist. = (5). 9 C. Such an equation would require that the Wronskian is constant-valued. Since w (sin x², cos x²) = 0 for x = 0 and W (sin x². cos x²) #0 for x0, such an equation cannot exist D. Such an equation would require that the Wronskian is zero for every point on the real line. Since W (sin x² cos x²) #0 for x * 0, such an equation cannot exist f 9 neither can be expressed as the other raised to a constant exponent. neither is the sum of the other and a constant 9 9 fg Y2 fa 0000 H a constant-valued function (5) fg-fg (6) sin lg-f'g fg-1g € (2) vanishes at x = 0 because it has a factor of (6). CO (2) is not ISS a constant-valued (3) is nol B