3(a) Calculate the convolution of the two signals y[n] = x[n] *h[n], where x[n] is defined in Fig. 10 and h[n] is defined in Eqn 15.

3(b) In fig 10, move the convolution machine from left to right and calculate y[n] by hand for n=0 to 4.

Fig 10.
Eqn 15:
$h[n]=\left(\frac{1}{2}\right)^{n} u[n]=\sum_{i=0}^{\infty}\left(\frac{1}{2}\right)^{i} \delta[n-i]$

Question

3(a) Calculate the convolution of the two signals y[n] = x[n] *h[n], where x[n] is defined in Fig. 10 and h[n] is defined in Eqn 15.

3(b) In fig 10, move the convolution machine from left to right and calculate y[n] by hand for n=0 to 4.

Fig 10.

Eqn 15:

$h[n]=\left(\frac{1}{2}\right)^{n} u[n]=\sum_{i=0}^{\infty}\left(\frac{1}{2}\right)^{i} \delta[n-i]$

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Expert Answer to - 3(a) Calculate the convolution of the two signals y[n] = x[n] *h[n], where x[n] is defined in Fig. 1

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Solution for - 3(a) Calculate the convolution of the two signals y[n] = x[n] *h[n], where x[n] is defined in Fig. 1

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This an additional answer to - 3(a) Calculate the convolution of the two signals y[n] = x[n] *h[n], where x[n] is defined in Fig. 1

(Solved): 3(a) Calculate the convolution of the two signals y[n] = x[n] *h[n], where x[n] is defined in Fig. 1 ...