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(Solved): 2. The moment of inertia of a dumbbell (see figure) is given by I=21ml21/21/201/21/ ...


2. The moment of inertia of a dumbbell (see figure) is given by \[ I=\frac{1}{2} m l^{2}\left(\begin{array}{ccc} 1 / 2 & -1 /

2. The moment of inertia of a dumbbell (see figure) is given by a. Find the eigenvalues b. Find eigenvectors c. Diagonalize the matrix


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Solution: According to given question, we have the moment of inertia of a dumbbells is given by :I=12ml2[12?120?12120001].Let us assume that : A=[12?1
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