(Solved):
2. Pressurized cabin to operate under 20Bar static service pressure The cover is tightened with ...
2. Pressurized cabin to operate under 20Bar static service pressure The cover is tightened with a suitable pre-tension force (F) with the help of 10M14 bolts of 5.8 quality. Cover and cylinder material is made of GG20 cast iron material. E-210 GPa, E-75 GPa, at 15mm a) Calculate the strength safety of the bolts. b) Calculate the non-splitting safety of the intermediate plates. c) T to be applied for the appropriate tensile strength to be created in the bolts Calculate the torque. T=K?Fi??d2?kb?=AECL
To calculate the strength safety of the bolts, we need to determine the maximum force applied to each bolt. The pressure inside the pressurized cabin is given as 20 bar, which is equivalent to 20 * 10^5 Pa.a) Strength Safety of Bolts:
The area of each bolt can be calculated using the formula:A = ? * (d^2) / 4Where:
A = Area of the bolt
d = Diameter of the boltFor M14 bolts, the diameter (d) is 14 mm, which is equivalent to 0.014 m.A = ? * (0.014^2) / 4
A ? 0.00015386 m²The force applied to each bolt can be calculated using the formula:F = P * AWhere:
F = Force applied to the bolt
P = Pressure inside the pressurized cabinF = (20 * 10^5) * 0.00015386
F ? 3077.2 NThe tensile strength of the bolt can be determined from the bolt's material properties. For a 5.8 quality bolt, the ultimate tensile strength (UTS) can be assumed to be approximately 580 MPa, which is equivalent to 580 * 10^6 Pa.The strength safety of the bolts is given by the ratio of the UTS to the force applied:Strength Safety = UTS / F
Strength Safety = (580 * 10^6) / 3077.2
Strength Safety ? 188546.5Therefore, the strength safety of the bolts is approximately 188546.5.