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(Solved): 10 The steady-state approximation can be used for the Lindemann mechanism bec ...



10 The steady-state approximation can be used for the Lindemann mechanism because (a) A* always decomposes very rapidly to pr???????

10 The steady-state approximation can be used for the Lindemann mechanism because (a) A* always decomposes very rapidly to products, (b) A* is deactivated very efficiently to \( A,(c) \) the concentration of the collision partner \( [\mathrm{M}] \) is always very large, (d) very few products are formed, (e) more than one of the above. (Specify which.)


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