(Solved): 1) Surface tension of water is 72.7mNm1 and its density is 0.998gcm3 at 20C. Assume th ...
1) Surface tension of water is 72.7mNm?1 and its density is 0.998gcm?3 at 20?C. Assume that contact angle is zero and calculate the rise of water level in a capillary tube of radius (a) 1mm and (b) 10?3cm. Given.: g=9.81ms?2. (c) If the water at 25?C rises through 7.36cm in a capillary of diameter 0.4 mm, estimate the surface tension of water at that temperature. Key: (a) 1.485cm; (b) 148.5cm; (c) 72mNm?1 2) The density of Hg is 13.6g/cm3 and surface tension is 0.47Nm?1. If the contact angle is 140?, calculate the capillary depression in a tube of 1mm diameter at 20?C. Kev: ?1.079cm
To calculate the rise of water level in a capillary tube, we can use the equation:h = (2 * T * cos?) / (? * g * r)where:
h is the rise in water level,
T is the surface tension of water,
? is the contact angle (assumed to be zero),
? is the density of water,
g is the acceleration due to gravity,
r is the radius of the capillary tube.