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(Solved): 1) Surface tension of water is 72.7mNm1 and its density is 0.998gcm3 at 20C. Assume th ...



1) Surface tension of water is \( 72.7 \mathrm{mNm}^{-1} \) and its density is \( 0.998 \mathrm{~g} \mathrm{~cm}^{-3} \) at \
1) Surface tension of water is and its density is at . Assume that contact angle is zero and calculate the rise of water level in a capillary tube of radius (a) and (b) . Given.: . (c) If the water at rises through in a capillary of diameter 0.4 , estimate the surface tension of water at that temperature. Key: (a) ; (b) ; (c) 2) The density of is and surface tension is . If the contact angle is , calculate the capillary depression in a tube of diameter at . Kev:


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To calculate the rise of water level in a capillary tube, we can use the equation:
h = (2 * T * cos?) / (? * g * r)

where: h is the rise in water level, T is the surface tension of water, ? is the contact angle (assumed to be zero), ? is the density of water, g is the acceleration due to gravity, r is the radius of the capillary tube.


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